3k^2+k+12=2

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Solution for 3k^2+k+12=2 equation: 



3k^2+k+12=2

We move all terms to the left:

3k^2+k+12-(2)=0

We add all the numbers together, and all the variables

3k^2+k+10=0

a = 3; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·3·10
Δ = -119
Delta is less than zero, so there is no solution for the equation

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